the proof for P IMPLIES Q also proves NOT Q IMPLIES NOT P, and vice versa
Hence we can prove P IMPLIES Q by proving its contrapositive
Use when the reverse direction is easier to prove than the original
Proof using contradiction
Assume predicate logic P, then by P and some axioms we come to a contradiction, hence NOT P
Proof for existence
Find a single example, show the predicate logic applies
Proof about a sequence
It is not much different as proving a regular expression, the key is to take the sequence definition as predicates, often works better if you write out the first 10 terms of the sequence to visualize it.
No comments:
Post a Comment